ΘΕΜΑ: Dictionaries

name=raw_input('Enter file:')
fhand=open(name,'r')
counts=dict()           # Keno dictionary.
for line in fhand:	
	if not line.startswith('From '):continue
	words=line.split()
	emails=words[1] # H prwti lexi, meta to 'From '.
 
	for email in emails:	
		counts[email]=counts.get(email,0)+1
	print emails

emails =["johny@gmail.com",
        "johny1@gmail.com",
        "other_johny@yahoo.com",
         "johny2@gmail.com",
        "johny@gmail.com",
        "other_johny@yahoo.com",
         "johny@gmail.com"]
 
count_emails = {}
 
for email in emails:
    if not email in count_emails.keys():
        count_emails[email] = 1
    else:
        count_emails[email] = count_emails[email] + 1
 
for k, v in count_emails.items():
    print(k, v)

file_name = input("Δώσε το όνομα του αρχείου: ")
 
file = open(file_name, "r")
 
emails_count = {}
 
for line in file:
 
    #Βλέπω εάν η γραμμή μου εμπεριέχει την λέξη From.
    if line.startswith("From"):
        words = line.split() #Xωρίζω τις λέξεις.
        email  = words[1]   #Πέρνω την δεύτερη λέξη που ειναι το email.
 
        #-----------Αυτο είναι το κομμάτι που δεν ήξερες πως να κάνεις-----------#
        #Εάν είναι η πρώτη φορά που βάζω αυτό το email στο
        #λεξικό μου, τότε του αναθέτω αρχική τιμή ένα.
        if email not in emails_count.keys():
            emails_count[ email ] = 1 #Δημιουργώ ένα "κλειδή λεξικού" και του δίνω την τιμή ένα.
 
        #Υπάρχει ήδη το email στο λεξικό μου που σημένει ότι τώρα πρέπει
        #να το αυξήσω κατά ένα γιατί το έχω ήδη δει τουλάχιστον μία φορά.
        else:
            emails_count[ email ] += 1 #Αυξάνω την μέτρηση του συγκεκριμένου email κατά ένα.
        #-----------Αυτο είναι το κομμάτι που δεν ήξερες πως να κάνεις-----------#
 
 
 
for key in emails_count.keys():
    print("Το email:",key,"εμφανίζεται:",emails_count[key],"φορές.")
 

From: nbampaliaris@gmail.com
	Hello there mate! I sended you this email...
 
 
 
From: nbampaliaris@gmail.com
	Hello there again!....
 
 
From: petrosIwannidis@yahoo.gr
	Mr, i would like to report you.....
 
 
From: anastasiaGianoudi@hotmail.com
	Hello Nick!......

counts["Όνομα_Κλειδιού"] = τιμή

variable = counts["Όνομα_Κλειδιού"]

KEYS = counts.keys()
 
for key in KEYS:
    print(key)

for line in fhand:	
	1)if not line.startswith('From '):continue
	2)words=line.split()
	3)emails=words[1] # H prwti lexi, meta to 'From '.
 
 
	4)for email in emails:
		counts[email]=counts.get(email,0)+1
	5)print emails

name=raw_input('Enter file:')					# Prompt the user to enter a file name.
fhand=open(name,'r')						# Open the file to read.
emails_counts=dict()						# Create an empty dictionary.
for line in fhand:	
	if line.startswith('From '):				# Condition, to manipulate with lines, starting with 'From '.
		words=line.split()				# We split the total text into single words.
		email=words[1]					# Assign in emails, the second words, which is the email address.
		if email not in emails_counts.keys():	        # Check, every email if it is in the dictionary, else add it and increase the counter by 1.
			emails_counts[email]=1
		else:
			emails_counts[email]+=1
maxval=None 							# Starting values for maxval and maxkii.
maxkii=None 									
for kii,val in emails_counts.items():			        # For loop through the dictionary .items(), which are (key:value).
	if maxval==None or maxval < val:	
		maxval=val
		maxkii=kii
print maxkii,maxval					        # Print the maximum key(maxkii) and maximum value (maxval).

name=raw_input('Enter file:')			
fhand=open(name,'r')
count=dict()
 
for line in fhand:	
	if line.startswith('From '):	
		words=line.split()
		email=words[1]
		count[email]=count.get(email,0)+1 	
 
maxval=None
maxkii=None
for kii,val in count.items():	
 
	if maxval==None or maxval < val:	
		maxval=val
		maxkii=kii
 
print maxkii, maxval			
 

from collections import Counter
 
def parse_emails():
    # implement your own 
    return ["a", "b", "c", "a", "a", "b", "a", "d", "e"]
 
emails = parse_emails()
histogram = Counter(emails)
print(histogram.most_common(2))      # [('a', 4), ('b', 2)]